The value of Kw is 9.55 x 10- 1 4 at a certain temperature. Calculate the pH of water at this temperature.
Solution
Kw = 9.55 x 10- 1 4
For water [H3O+] = [OH-]
If, Kw = [H3O+] [OH-] = 9.55 x 10- 1 4 then,
[H3O+] [H3O+] = 9.55 x 10- 1 4
[H3O+]2 = 9.55 x 10- 1 4
In the last step we have taken hydronium and hydroxyl ion concentration to be equal.But if it is so then the pH will be 7.It means we are already assuming the thing which we need to find.
Help me Please.In am very confused in numericals of this chapter
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Answer:
First of all you mast know the basic of the lesson
Explanation:
for example if you are listening will in your class but you didn't understand the topic that means you must need basics I suggest that install khan academy to learn all
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