Question

The value of Lim h—0 sin(x+h)log(x+h)-sinxlogx /h

Answer 1

Answer:

Lim Sin(x+h)log(x+h)-sinxlogx /h

0/0 form use D-L hospitalization rule :

Lim {Cos(x+h).log(x+h) + Sin(x+h)/(x+h) } / 1

Lim {cosx.logx + (sinx/x)}

= (xcosx.logx+sinx)/x

Answer 2

Step-by-step explanation:

2x-1 is the answer .

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