The value of lim x— 1 cos(pi/2 .x)/1- root under x
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Answer:
π is final answer . for more answers follow me.
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Step-by-step explanation:
lim cos(π/2x) / (1- √x)
0/0 form then apply D-L hospitalization rule :
lim (-sin π/2x)*(-π/2x^2) / (-1/2)(x^ -1/2)
at x = 1
lim (-1)*(-π/2) / (-1/2)
= (π/2) / (-1/2)
= -π
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