Question

The value of Lim x—1 sec pi/2x . Log x

Answer 1

Step-by-step explanation:

Lim {sec π/2x . logx }

equation form 0*infinity so Change in 0/0 form

= Lim { log x / cos π/2x }

now apply D-L hospitalization rule :

= Lim { (1/x )/ (-π/2x^2)* (-sin π/2x) }

at x= 1

= Lim (1)/(-π/2)*(-1)

= 2/π