Question

The value of log 1/3 to the base 9​

Answer 1

Answer:

$log_{9}\:\frac{1}{3}\\=\frac{-1}{2}$

Step-by-step explanation:

$log_{9}\:\frac{1}{3}\\=log_{3^{2}}\:3^{-1}\\=\frac{-1}{2}\:log _{3}3$

$\boxed {log_{a^{n}}\:a^{m} = \frac{m}{n}}$

$= \frac{-1}{2}$

Therefore,

$log_{9}\:\frac{1}{3}\\=\frac{-1}{2}$

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