Question

the value of log 1.3bar with the base of 3/4​

Answer 1

Answer:

$log_{0.75}(1.3) = \frac{log \: 1.3}{log \: 0.75} = \frac{0.1139}{log75 - log100 } \\ = \frac{0.1139}{1.875 - 2} = \frac{0.1139}{ - 0.125} = - 0.9112$

Answer 2

Answer:

this is correct.......................