Question

The value of log base 32 root 2​

Answer 1

Answer:

The correct answer is 1/10

Step-by-step explanation:

$log_{32}( \sqrt{2} ) = log_{32}( {2}^{ \frac{1}{5} } ) = log_{32}( {32}^{ \frac{1}{5} \times \frac{1}{2} } ) = log_{32}( {32}^{ \frac{1}{10} } ) = \frac{1}{10} \times log_{32}(32) = \frac{1}{10} \times 1 = \frac{1}{10}$

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