The value of log10 (1250)+log10 (80) is
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Answer: log10 (1250)+log10 (80)= log10(125*80) = log10(10000) =log10(10^4) = 4log10(10) =4
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Answered by
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Answer:
log x + log y=logxy
so,log1250+log 80 =
log 1250*80 = log100000 base 10
=
so by simplifying X= 5
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