Question

: the value of log3 9 – log5 625 + log7 343 is

Answer 1

The value of given expression is 1.

Step-by-step explanation:

The given expression is

$log_39-log_5625+log_7343$

This expression can be rewritten as

$log_3(3)^2-log_5(5)^4+log_7(7)^3$

Using the properties of logarithm, we get

$2-4+3$                            $[\because log_aa^x=x]$

$1$

Therefore, the value of given expression is 1.

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Answer 2

The value of the expression is 1.

Explanation:

The given expression : $\log_3 9 - \log_5 625 + \log_7 343$

Since , $9=3^2$

$625=5^4$

$343=7^3$

By using these values the given expression would become :

$\log_3 3^2 - \log_5 5^4 + \log_7 7^3$

Property of logarithm: $\log_aa^b=b$

Our expression would become ,

$2 - 4 + 3=1$

∴ The value of the expression is 1.

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