Question

The value of log5.log2. log3.log512base2 is

Answer 1

Answer:

$log_5(log_2(log_3(log_2{512})))=0$

Step-by-step explanation:

Formula used:

$log_a{M^n}=n\:log_aM$

$log_a{a}=1$

$log_a{1}=0$

Now,

$log_5(log_2(log_3(log_2{512})))$

$=log_5(log_2(log_3(log_2{2^9})))$

$=log_5(log_2(log_3(9log_2{2})))$

$=log_5(log_2(log_3(9(1))))$

$=log_5(log_2(log_3{9}))$

$=log_5(log_2(log_3{3^2}))$

$=log_5(log_2(2log_3{3}))$

$=log_5(log_2(2(1)))$

$=log_5(log_2{2})$

$=log_5{1}$

$=0$ (using formula (3))

Answer 2

Determine the value of log5+log2