Math, asked by alinakincsem460, 11 months ago

The value of logabc a3b3c3 is

Answers

Answered by pranit68
10

Answer:

Answer is 3

Step-by-step explanation:

logabc (abc)^3

3logabc abc

=3

Answered by pulakmath007
2

 \sf The  \: value  \: of \:  \:  log_{abc}( {a}^{3}  {b}^{3}  {c}^{3} )  =  \bf 3

Given :

 \sf \: log_{abc}( {a}^{3}  {b}^{3}  {c}^{3} )

To find : The value

Tip :

Formula to be implemented

 \sf{1.  \:  \: \:  log( {a}^{n} ) = n log(a)  }

 \sf{2. \:  \:  log(ab) =  log(a)   +  log(b) }

 \displaystyle \sf{3. \:  \:  log \bigg( \frac{a}{b}  \bigg)  =  log(a) -  log(b)  }

 \sf{4. \:  \:   log_{a}(a)   = 1}

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

 \sf \: log_{abc}( {a}^{3}  {b}^{3}  {c}^{3} )

Step 2 of 2 :

Find the value

 \sf \: log_{abc}( {a}^{3}  {b}^{3}  {c}^{3} )

 \sf  =  log_{abc} {(abc)}^{3}

 \sf  =3  \times  log_{abc} {(abc)}^{}

 \sf  =3  \times  1

 \sf  =3

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