The value of (logm+logm
2
+logm
3
+...+logm
n
) is equal to
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0
Answer:
ogm+logm
2
+logm
3
+...+logm
n
=log(m.m
2
.m
3
...m
n
)
=logm
(1+2+3+...n)
=logm
2
n(n+1)
=
2
n(n+1)
logm
Step-by-step explanation:
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