The value of logx =2.301 then find the value of x
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Find the value of x in 2logx+log5=2.69897 So far I got: 2logx+log5=2.69897 ⇒logx2+log5=2.69897 ⇒log5x2=2.69897 What should I do next? Note: ...
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Remember, if ax=b, then loga(b)=x log10(5x2)=2.69897 102.69897=5x2 x2=102.698975 x=±√102.69897 ...
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