Question

The value of m for the last electron of d3 is​

Answer 1

To find:

Value of "m" for the last electron in d³ orbital ?

Calculation:

"m" here refers to Magnetic Quantum Number representing the orientation of each orbital with reference to the co-ordinate axes.

So, a d³ orbital in box diagram looks like this:

${d}^{3} \rightarrow \: \boxed{ \uparrow | \uparrow | \uparrow | \:\_\: |\:\_ \: }$

Now, the Magnetic Quantum Number can be assigned as follows:

${d}^{3} \rightarrow \: \boxed{ \: \uparrow \: | \: \uparrow \: | \: \uparrow | \: \_ \: | \: \_ \: } \\\\ \implies \: \: d_{xy} \: \:d_{yz} \: \: d_{ {z}^{2} } \: d_{xz} \: d_{ ({x}^{2} - {y}^{2} )} \\\\ \implies \: - 2 - 1 \: \: \: \: \: \: 0 \: \: \: \: 1 \: \: \: \: \: 2$

From the above distribution, we can say that the last electron of d³ orbital has Magnetic Quantum Number to be zero (0).

Hope It Helps.