Question

The value of m for which straight line 3x-2y+z+3=0=4x-3y+4z+1 is parallel to the plane 2x-y+mz-2=0

Answer 1

tama di nya ako mahal kasi may iba na sya medj hurt na sakin ah

Answer 2

Answer:

-2

Step-by-step explanation:

Direction ratios of normals to planes are (3,−2,1) and (4,−3,4) respectively.

So direction ratio of the required line is the cross product of these normals

i.e. ∣∣∣∣∣∣∣∣i34j−2−3k14∣∣∣∣∣∣∣∣

On expanding the determinant we get;

−5i−8j−k

Therefore, direction ratio of line is (5,8,1)

Now line is parallel to 2x−y+mz−2=0, So dot product of direction ratio of line and normal to plane must be 0

∴10−8+m=0

⇒m=−2

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