The value of m for which the equation x² + 2(m + 1)x + m² = 0 has equal roots is *
The value of m for which the equation x² + 2(m + 1)x + m² = 0 has equal roots is *
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Equation given: x^2 + 2mx + m - 2x + 5 = 0
(rewriting the equation)
x^2 + (2mx – 2x) + (m + 5) = 0
x^2 + 2(m - 1)x + (m + 5) = 0 ---------- ①
For the roots to be equal, the discriminant (D = b^2 – 4ac) must equal 0,
i.e.,
b^2 – 4ac = 0 ,
Where, a = 1, b = 2(m – 1), c = (m + 5)
[2(m – 1)]^2 – 4(1)(m + 5) = 0,
4(m^2 – 2m + 1) – 4(m + 5) = 0,
(m^2 – 2m + 1) – (m + 5) = 0,
m^2 – 2m + 1 – m – 5 = 0,
m^2 – 3m – 4 = 0,
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