The value of M if one root is 2 of f(x) = 2x2+4X-6 = 0
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Given : f(x) = 2x²+Mx-6 = 0
One root is 2
To Find: Value of the M
Solution:
2x²+Mx-6 = 0
One root is 2
=> 2(2)² + M(2) - 6 = 0
=> 8 + 2M - 6 = 0
=> 2M + 2 = 0
=> M + 1 = 0
=> M = -1
The value of M is - 1
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