Question

The value of machine depreciates every year by 10% ,if the present value of the machine is Rs.81,000, then find the value of machine (i) next year(ii) previous year

Answer 1

Let the value of machine 2 year ago is x

Thenx×  

100

90

​  

×  

100

90

​  

=162000

⇒x=  

90×90

162000×100×1000

​⇒x=20000

Answer 2

$\rule{300}2$

Your Question:

The value of machine depreciates every year by 10% ,if the present value of the machine is Rs.81,000, then find the value of machine (i) next year(ii) previous year.

$\rule{300}2$

Your Answer:

Given:-

• The present value is 81,000
• The value is decreasing at the 10% every year

To Find:-

• Value of machine next year
• Value of machine previous year

Solution:-

We have to find 10% of 81,000

So, 10% of 81000 is

$\tt 81000 \times \dfrac{10}{100} \\\\ \tt \Rightarrow 8100$

So, the value of machine next year will be

81000 - 8100 = 72900

And let the value of machine previous year be x

So, 10 percent of x will be x/10

And satisfies this equation

$\tt x -\dfrac{x}{10} = 81000 \\\\ \tt \Rightarrow \dfrac{9x}{10} = 81000 \\\\ \tt \Rightarrow x = 81000 \times \dfrac{10}{9} \\\\ \tt \Rightarrow x = 90000$

So, value of machine previous year will be 90000

$\rule{300}2$