Question

the value of machine depreciates every year by 8%. what will be its value after 2 year if its present value is rupees 25000

hlw toi hai​

Answer 1

Answer:

The answer is Rs. 21,160

Explanation:

Here,

We have,

Present price (P) = Rs. 25000

Depreciation Rate (R) = 8%

Time (T) = 2 years

Now,

Price after 2 years (Pt)

= P [ 1 - (R/100) ]^T

= 25000 [ 1 - (8/100) ]^2

= 25000 * 0.8464

= Rs. 21,160.