Question

the value of machine is 500000is depreciating at the rate of 10%every year in how many year it will be reduced to rs 364500

Answer 1

3 years
first year reduced to 450000
second year 405000
and in third year 364500

Answer 2

Solutions 

10% of 500,000 

= 10/100 * 500,000 

= 0.10 * 500,000 = 50,000 

500,000 - 50,000 = 10% 

500,000 - 50,000 = 450,000

10% of 450,000 

450000/x=100/10
(450000/x)*x=(100/10)*x       - we multiply both sides of the equation by x
450000=10*x       - we divide both sides of the equation by (10) to get x
450000/10=x 
45000=x 
x=45000

10% = 450,00

450,000 - 450,00 = 40,500

40,500 - 4050 = 3664500 

It will be 3th year.