Question

The value of machine reduces
machine reduces by 20% per
year
if the present value of the machine is rs. 30000
what will be its value after
one year?​

Answer 1

Answer:

the boundary of the boundary of the boundary of the boundary of the boundary of the boundary of the boundary of the boundary of the boundary of the boundary of the boundary

Answer 2

Let the required number of years = n years

∴ Value of machine after n years = Its value when new (1− r/100)^n

⇒Rs.128000=Rs.250000(1− 20/100)^n

Rs.128000/Rs 25000=80/100^n=4/5^n

On simplifying, we get :

(4/5)^3=(4/5^n) = n = 3 years