Physics, asked by sharmaanand5213, 10 months ago

the value of n so that vector (2i-3j+k) may be perpendicular to the vector (3i+4j+nk) is.

Answers

Answered by mohammadsaqib3642
6

a.b = abcos(theta)

When theta equal to pi/2 then cos(theta) is become zero then

a.b=0

(2i-3j+k).(3i+4j+nk) = 0

6-12+n=0

n=6

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