Question

The Value of nC1​+n+1C2​+n+2C3​+...+n+m−1Cm​ is equal ​

Answer 1

Step-by-step explanation:

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Answer 2

agoN(C1+C2+......Cr)+( (2-1)C2+(3-1)C3......) SUMMATION Cr + SUMMATION rCrSUMMATION Cr is 2^nAnd to solve rCr write expansion of (1+x)^n and differentiate and then put x=1

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