Question

the value of √ over√6+√6+√6​

Answer 1

Answer

Letx=

6+

6+

6+

6+...∞

On squaring both sides,

x

2

=6+

6+

6+

6+

6+...∞

x

2

=6+x

x

2

−x−6=0

x=

2(1)

1±

1

2

−4×1×(−6)

x=

2

1±

25

=

2

1±5

∴x=3 or x=−2

Since a negative number cannot be under root, hence x=3

Answer 2

Answer:

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