Question

the value of p(1/2) for p(z) = z⁴-z²+z​

Answer 1

please mark my answer brainliast

Answer 2

$Given \: p(z) = z^{4} - z^{2} + z$

$Value \: of \: p\Big( \frac{1}{2}\Big) \\= \Big(\frac{1}{2}\Big)^{4} - \Big(\frac{1}{2}\Big)^{2} +\frac{1}{2}\\= \frac{1}{16} - \frac{1}{4} + \frac{1}{2} \\= \frac{1-4+8}{16} \\= \frac{5}{16}$

Therefore.,

$\red{ Value \: of \: p\Big( \frac{1}{2}\Big)}\green { = \frac{5}{16}}$

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