Question

the value of p(1/4) if p(x)=12x2-7x+1​

Answer 1

Answer:

p(x)=12x²-7x+1

p(1/4)=12(1/4)²-7(1/4)+1

=12×1/16-7/4+1

=3/4-7/4+1

=3-7+4/4

= -8/4

=-2

Therefore the value of p(1/4) is -2

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Answer 2

Given -

$p(x) = {12x}^{2} - 7x + 1$

$p( \frac{1}{4} )$

To,

Find the value of

$p( \frac{1}{4})$

Solution -

$=> p(x) = {12x}^{2} - 7x + 1$

$=> p( \frac{1}{4}) = {12}{ (\frac{1}{4})}^{2} - 7( \frac{1}{4}) + 1$

$=> \frac{12}{16} - \frac{7}{4} + 1$

After taking LCM of 16 and 4 -

$\large = > \: \frac{24 - 14 + 1}{8}$

$\large = > \frac{9}{8}$

$\therefore$ the value of p(1/4) is 9/8

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