Question

the value of P (-1) when p(x) is x cube - 3 x square +5 is​

Answer 1

Answer:

p(x)=x^3-3x^2+5

to find p(-1)

p(-1)=(-1)^3-3×(-1)^2+5

we know that -1 raised to any odd numbers is -1 itself and same raised to any even number is 1.

therefore, it becomes

p(-1)=(-1)-[3×(1)]+5

= -1-3+5

= -4+5

= 1

p(-1)=1..

hence solved.

Answer 2

= x^3-3x^2+5

=(-1)^3 -3(-1)^2+5

=(-1)-3+5

=(-4)+5

=1

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