Math, asked by HARINI, 1 month ago

the value of p(×)=4×^3+3×^2+2×+1 at×=1 is​

Answers

Answered by DanielSanthosh
1

Answer:

p  =4

Step-by-step explanation:

The given pair of linear equation :

⇒  (p+2)x−(2p+1)y=3(2p−1)                    ------ ( 1 )

⇒  2x−3y=7                             ------- ( 2 )

On comparing with equations,

a  

1

x+b  

1

y+c  

1

=0

and a  

2

x+b  

2

y+c  

2

=0

We get, a  

1

=(p+2),b  

1

=−(2p+1),c=−[3(2p−1)]

a  

2

=2,b  

2

=−3,c=−7

⇒    

a  

2

 

a  

1

 

=  

2

p+2

 and  

b  

2

 

b  

1

 

=  

−3

−(2p+1)

 

A pair of linear equations has a unique solution, if  

⇒    

a  

2

 

a  

1

 

 

=  

b  

2

 

b  

1

 

 

⇒    

2

(p+2)

 

=  

−3

−(2p+1

 

⇒  −3(p+2)

=2(−2p−1)

⇒  −3p−6

=−4p−2

⇒  −3p+4p

=−2+6

⇒  p

=4

Answered by selenarmy7
3

Answer:

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