Question

"The value of p(4) is * –268 -168 -252 -164​

Answer 1

Answer:

Answer:

${y {x}^{2} + 2yz} \: \: \: 2 {x}^{2} - yz$

Perimeter of the rectangle = 2(70 +B). B = 58 m. Area of the rectangle = 58 *70 = 4,060 sq m. Area of the square = length * length = 64 *64 = 4096 sq.

If a=2and b=3 then find the value of the following

(a÷b+b÷a)³ ${y {x}^{2} + 2yz} \: \: \: 2 {x}^{2} - yz$

Answer 2

Answer:

Answer:

Answer:

${y {x}^{2} + 2yz} \: \: \: 2 {x}^{2} - yz$

Perimeter of the rectangle = 2(70 +B). B = 58 m. Area of the rectangle = 58 *70 = 4,060 sq m. Area of the square = length * length = 64 *64 = 4096 sq.

If a=2and b=3 then find the value of the following

(a÷b+b÷a)³ ${y {x}^{2} + 2yz} \: \: \: 2 {x}^{2} - yz$