Question

The value of p for the equation x2 – px + 9 = 0 to have equal roots is _____​

Answer 1

Step-by-step explanation:

Px(x-3) + 9 = 0 px2-3px+9=0 a=p , b=-3p , c=9 b2-4ac= (-3p)2-4(p)(9) =9p2-36p for having equal roots b2-4ac = 9p2-36p = 0 9p2-36p = 0 9p(p-4) = 0

Answer 2

here's your answer my dear...