Math, asked by AKSHAYKRJHA, 3 months ago

the value of p for which p(i^+^j+k^) is a unit vector​

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Answered by Anonymous
4

Answer:

The magnitude of the vector p ( ^ i + ^ j + ^ k ) (i^+j^+k^) is √ p 2 + p 2 + p 2 = √ 3 p 2 = ± √ 3 . p2+p2+p2=3p2=±3. ( ∵ √ p 2 = ± p ) (∵p2=±p) Given that p ( ^ i + ^ j + ^ k ) (i^+j^+k^) is a unit vector. Therefore, the magnitude of the vector p ( ^ i + ^ j + ^ k ) (i^+j^+k^) is 1. Therefore, Hence, for p = ± 1 √ 3 , p ( ^ i + ^ j + ^ k ) ±13,p(i^+j^+k^) is a unit vector.

Answered by Anonymous
6

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