Question

The value of P for which the equation Px² + 8x + 1 = 0 has equal roots

Answer 1

Answer:

Given Equation : px² - px + 1 = 0

On comparing the given equation with a²x+ bx + c = 0 we get that the value of a is p , value of b is - p and the value of c is 1 .

Discriminant = b² - 4ac

In the question discriminant will be 0 as the equation has real & equal roots.

b² - 4ac = 0

( - p )² - 4( 1 × p ) = 0

p² - 4 p = 0

p( p - 4 ) = 0

By Zero Product Rule, value of p is 0 or 4. As p is also with x² , it can't be 0 because if it is 0 , given equation can't be a quadratic equation.

Therefore, value of p is 4.

Answer 2

Answer:

Step-by-step explanation:

This is the answer hope it helps