Math, asked by kanchanpandey7703, 6 months ago

The value of p for which the numbers x, 2x+p and 3x+6 are three consecutive terms of an AP is​

Answers

Answered by havarjun5
0

Answer:

3

Step-by-step explanation:

since x, 2x+p and 3x+6 are in AP

x+3x+6=2*(2x+p)

after simplifying you get p=3

Answered by IshitaAgarwal05
1

Answer:

p = 3

Step-by-step explanation:

Since, x, 2x+p, 3x+6 are 3 consecutive terms of an AP,

Therefore, 2x+p - x = 3x+6 - (2x+p)

⇒ x+p = x+6-p

⇒ 2p = 6

p = 3

Hope this helps.....

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