Question

the value of p for which the pair of linear equations px-y=2 and 6x-2y-3 will have infinitely many solutions ​

Answer 1

• p divided by 6=-1 divided by -6=3

Answer 2

There is no value of P

Step-by-step explanation:

condition for two lines $a_1x+b_1y +c_1=0 ,a_2x+b_2y +c_2=0$ to have infinite many solutions is

$\frac{a_1}{a_2}= \frac{b_1}{b_2}= \frac{c_1}{c_2}$

here

$a_1 = p\\a_2 = 6 \\b_1 = -1\\b_2 = -2\\c_1 = -2\\c_2 = -3$

therefore ,

$\frac{a_1}{a_2}= \frac{b_1}{b_2}= \frac{c_1}{c_2}\\\\\frac{p}{6}= \frac{-1}{-2}=\frac{-2}{-3}\\\\\frac{p}{6}=\frac{-1}{-2} \\\\\text{we get}\\\\\p = 3\\\\\frac{p}{6}=\frac{-2}{-3}\\\\\text{we get} \\\\p = 4$

As p has two different values , therefore , there will be no value for p for which the pair of equations will have infinitely many solutions

hence , There is no value of P

#Learn more :

For what values of p will the following pair of linear equation have infinitely many solution

• px-4y = 3

• 6x-12y = 9

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