Question

The value of p for which the polynomial px³+4x²-px+8
exactly divisible by (x+2) is
A =0
ß = 3
C =5
D = 4​

Answer 1

Answer:

D=4

Step-by-step explanation:

px³+4x²-px+8/x+2

If it divides by x+2 then it must a factor of x+2

So, put x= -2 in place of x

We get,

p(-2)^3+4(-2)^2-p(-2)+8=0

-8p+16+2p+8=0

-6p+24=0

-6p= -24

p=4

It will exactly divisible if p=4

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