Question

The value of p for which the polynomial xcube+4xsquare-px+8 is exactly divisible by x-2

Answer 1

Answer:

p=16

Step-by-step explanation:

put factor =0

x-2=0

x=2

q[x]=x^3+4x^2-px+8

q[2]=2^3+4*2^2-2p+8

put q[2]=0

8+16-2p+8=0

32-2p=0

-2p=-32

p=16