Question

The value of p for which the quadratic equation
2px²+ 6x + 5 = 0 has real and distinct roots is
a.1/2
b. 1
c.2
d.9/8​

Answer 1

Answer:

a. 1/2

Step-by-step explanation:

We know from the nature of roots in a quadratic equation that, for the roots to be real and distinct (or unequal) the Discriminant of the quadratic eqaution must be strictly positive.

ie.

$b^{2} - 4ac > 0$

Comparing the above eqaution, with the standard quadratic eqaution we get,

$36 - 40p^{2} > 0$

$40p^{2} < 36$

$p^{2} < \frac{36}{40}$

$p < \frac{6}{2 \sqrt{10} }$

$p < \frac{3}{ \sqrt{10} }$

ie. p must be less than 0.94, Hence option "a" satisfies the expression.

Answer 2

Answer:

above answer is right

Step-by-step explanation:

Just under stand every step from above answer