Question

the value of p for which the quadratic equation 5x square-px+1=0 has real roots.​

Answer 1

Answer:

Step-by-step explanation:

Hi friend,

Here is your answer,

_____________________________________________________________

If there are equal roots then D = 0

D = √(b²-4ac)

q(x) = px² - 5x + p

0   = √((-5)² - 4*p*p)

 0  = 25 - 4p²

4p² = 25

p²   = ²⁵/₄

p    = ⁵/₂

p = 2.5

For p = 2.5 the equation px² - 5x + p has equal roots.

_____________________________________________________________

★★★★ HOPE THIS HELPS YOU ★★★★

★★★★ PLS MARK ME AS BRAINLIEST ★★★★