Question

The value of p for which the quadratic equation x 2 -px+p+3=0 has reciprocal roots is

Answer 1

let roots be a,b
a* b=1
( p+3)=1
p=-2

Answer 2

Answer:

Step-by-step explanation:let the given root be x and y as x and y is reciprocal to each other then    $\frac{1}{y} =x$  so xy=1 and we know then product of root (xy)=p+3 and xy =1 putting xy=1 then 1=p+3  so value of p is -2