Question

the value of p for which the quadratic equation x(x-4)+p=0 has real roots is​

Answer 1

Answer:

4

Step-by-step explanation:

x(x-4)+p=0

x^2 - 4x + p =0

for real roots Delta=0

(-4)^2 - 4 (1)(p) = 0

16 - 4p = 0

16=4p

p=4