Question

the value of p for which the qurdratic equation x^2+px+4=0 has equal roots is ______​

Answer 1

Answer:

The answer of your question is:

Since roots are real, therefore discriminant will be 0.

$d = { b}^{2}-4ac$

$0 = {p}^{2} - 4 \times 1 \times 4$

${p}^{2} = 16$

$p = 4$

Answer 2

Answer:

Here ,a=1

b=p

c=4

b^2-4ac=0

Step-by-step explanation:

p^2-4.1.4=0

p^2-16=0

p^2=16

p^2=4^2

p=4