Question

The value of p for which the roots of the quadratic equation x2-2(p+1)x+p2=0 are real and equal is

Answer 1

Answer:

for roots to be real,

b2 -4ac must be 0

( -2(p+1))^2 -4(1)(p2) = 0

4(p2 + 1 + 2p ) -4p^2 =0

4p2 + 2p + 1 -4p2 = 0

2p +1 =0

p = -1/2