Question

The value of p for which the roots of the quadratic equation x2-2(p+1)x+p2=0 are real and equal is

Answer 1

Step-by-step explanation:

(p+1)sq-4p2=0

p2+2p+1-4p2

-3p2+2p+1

-(3p2-2p-1)

-(3p2-3p+p-1

-3p(p-1)+1(p-1)

(p-1)(1-3p)

p=1, 1/3