Question

The value of 'P' for which x-4 may be a factor of 5x³-(p+4)x²-px-(p+4)
plz tell fast it's a exam ​

Answer 1

Answer:

p = 12

Step-by-step explanation:

f(x) = 5x³ - ( p + 4)x² - px - (p + 4)

g(x) = x - 4

Zero Of g(x) =)x - 4 = 0

=)x = 4

By Reminder Theoram:-

f(4) = 0

=)5 x (4)³ - (p +4)4² -( p x 4) - (p + 4) = 0

=)(5 x 64) - (p + 4) 16 - 4p - (p + 4) = 0

=)320 - (16p + 64) - 4p - p - 4 = 0

=)320 - 16p - 64 - 4p - p - 4 =0

=)320 - 68 - 16p - p - 4p = 0

=)252 - 21p = 0

=)-21p = -252

=)p = 12

Hope it helped