Question

The value of P(n, n – 1) is

Answer 1

Step-by-step explanation:

p(n,n-1)

p^n r = n!/(n-r)!

p(n,n-1)= n!/(n-n+1)!= n!/1!=n!

Answer 2

Given,

$\[P\left( {n,n - 1} \right)\]$

To find,

The value of $\[P\left( {n,n - 1} \right)\].$

Solution,

Know that the formula of $\[P\left( {n,r} \right)\]$ is $\[\frac{{n!}}{{\left( {n - r} \right)!}}.\]$

Apply values.

$\[\begin{array}{l} \Rightarrow \frac{{n!}}{{\left( {n - \left( {n - 1} \right)} \right)!}}\\ \Rightarrow \frac{{n!}}{{\left( {n - n + 1} \right)!}}\\ \Rightarrow \frac{{n!}}{{\left( 1 \right)!}}\\ \Rightarrow n!\end{array}\]$

Hence, the required value is $\[n!.\]$