Question

The value of p, q, r, s in the following equation,
pNaHCO3 + Heat - qNa2CO3 + H2O + CO2​

Answer 1

Answer:

p=6, q=3, r=3, s=3

Explanation:

6NaHCO3+ Heat ---- 3Na2CO3 + 3H2O + 3CO2

Answer 2

Final answer: $p=2, q=1, r=1, s=1$

Given that: We are given, $pNaHCO_{3}$  → $qNa_{2}CO_{3} + rH_{2}O + sCO_{2}$.

To find: We have to find the value of p, q, r and s.

Explanation:

• To balance a chemical equation:

Identify and count each type of atom in reactants and products. Place coefficients in front of molecule to increase the number of atoms or molecules of the substances. Repeat these process until the equation is balanced.

• The given skeletal equation is:

$pNaHCO_{3}$  → $qNa_{2}CO_{3} + rH_{2}O + sCO_{2}$

• To equalize sodium on both side multiply $NaHCO_{3}$ by 2 and $Na_{2}CO_{3}$ by 1.

Then the equation become: $2NaHCO_{3}$  → $Na_{2}CO_{3} + rH_{2}O + sCO_{2}$

Number of sodium is equal on both side in the equation.

• Now check the number of carbon.

Left side of the equation contain 2 carbon. To equalize carbon on both side multiply $CO_{2}$ by 1.

Then the equation become: $2NaHCO_{3}$  → $Na_{2}CO_{3} + rH_{2}O + CO_{2}$

Number of carbon is equal on both side in the equation.

• Now check the number of oxygen and hydrogen.

Left side of the equation contain 2 hydrogen and 6 oxygen.

To equalize hydrogen and oxygen on both side multiply $H_{2}O$ by 1.

Then the equation become: $2NaHCO_{3}$  → $Na_{2}CO_{3} + H_{2}O + CO_{2}$

• The number of atoms on the left side of the equation become equals to number of same atoms on the right side of the equation. Hence given chemical equation is balanced.

• The balanced equation:

$2NaHCO_{3}$  → $Na_{2}CO_{3} + H_{2}O + CO_{2}$

• Compare it with given chemical equation:

$pNaHCO_{3}$  → $qNa_{2}CO_{3} + rH_{2}O + sCO_{2}$

• $p=2, q=1, r=1, s=1$

To know more about the concept please go through the links

https://brainly.in/question/44474395

https://brainly.in/question/17504198

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