Question

The value of p(t) = 2+t+2t^2−t^3 when t=0 is​

Answer 1

Answer:

substitute the values,

2 + 0 + 2(0)² - (0)³

2 + 0 - 0

= 2

Answer 2

Answer:

put value of t in p(t)

p(t) =2+ 0+2×0^2 - 0^3

=2+0+0-0

= 2

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