The value of p(t)=2+t+2t²-t³ for p(0) is
a) 1
b) 2
c) -1
d) 3
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4
Answer:
b) 2
Step-by-step explanation:
p(t) = 2+t+2t²-t³
p(t) = -t³+2t²+t+2
p(0) = ?
Put t = 0 ,
p(0) = -(0)³+2(0)²+0+2
p(0) = 0+0+0+2
p(0) = 2
The value of p(t)=2+t+2t²-t³ for p(0) is 2
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