Question

THE VALUE OF p(t) = 2+t + 2t² -t³ WHEN t=0 IS

Answer 1

Step-by-step explanation:

$p(t) = 2 + 0 + 2 \times {0 }^{2} + - {0}^{3} \\ = 2 + 0 + 0 + 0 \\ = 2 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Answer 2

Answer:

p(t) = 2 + t + 2t² - t³

p(0) = 2 + (0) + 2(0)² - (0)³

= 2 + (0) + 0 - 0

= 2