Question

the value of p(t)=2+t+2tsq-tcb when t=0 is​

Answer 1

Answer:

when t=0 then p(t) = 2

Step-by-step explanation:

p(t)=2+t+2tsq-tcb

p(0)=2+0+2(0)sq-(0)cb

=2+0+0+0

=2

hope it helps....